QuestionApril 23, 2025

What is the Delta S_(rxn) for the combustion of 1 mole of C(s) based on the reaction below? C(s)+O_(2)(g)arrow CO_(2)(g) Delta S^circ (C)=2J/molK;Delta S^circ (O_(2))=205J/molK;Delta S^circ (CO_(2))=213.74J/molK

What is the Delta S_(rxn) for the combustion of 1 mole of C(s) based on the reaction below? C(s)+O_(2)(g)arrow CO_(2)(g) Delta S^circ (C)=2J/molK;Delta S^circ (O_(2))=205J/molK;Delta S^circ (CO_(2))=213.74J/molK
What is the Delta S_(rxn) for the combustion of 1 mole of C(s) based on the reaction
below?
C(s)+O_(2)(g)arrow CO_(2)(g)
Delta S^circ (C)=2J/molK;Delta S^circ (O_(2))=205J/molK;Delta S^circ (CO_(2))=213.74J/molK

Solution
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Answer

6.74 \, \text{J/mol·K} Explanation 1. Write the formula for \Delta S_{rxn} \Delta S_{rxn} = \sum \Delta S^\circ (\text{products}) - \sum \Delta S^\circ (\text{reactants}) 2. Substitute given values \Delta S_{rxn} = [\Delta S^\circ (CO_2)] - [\Delta S^\circ (C) + \Delta S^\circ (O_2)] \Delta S_{rxn} = [213.74] - [2 + 205] 3. Perform the calculation \Delta S_{rxn} = 213.74 - 207 = 6.74 \, \text{J/mol·K}

Explanation

1. Write the formula for $\Delta S_{rxn}$<br /> $\Delta S_{rxn} = \sum \Delta S^\circ (\text{products}) - \sum \Delta S^\circ (\text{reactants})$<br /><br />2. Substitute given values<br /> $\Delta S_{rxn} = [\Delta S^\circ (CO_2)] - [\Delta S^\circ (C) + \Delta S^\circ (O_2)]$<br /> $\Delta S_{rxn} = [213.74] - [2 + 205]$<br /><br />3. Perform the calculation<br /> $\Delta S_{rxn} = 213.74 - 207 = 6.74 \, \text{J/mol·K}$
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