QuestionJune 13, 2025

The following chemical reaction takes place in aqueous solution: FeBr_(2)(aq)+(NH_(4))_(2)S(aq)arrow FeS(s)+2NH_(4)Br(aq) Write the net ionic equation for this reaction.

The following chemical reaction takes place in aqueous solution: FeBr_(2)(aq)+(NH_(4))_(2)S(aq)arrow FeS(s)+2NH_(4)Br(aq) Write the net ionic equation for this reaction.
The following chemical reaction takes place in aqueous solution:
FeBr_(2)(aq)+(NH_(4))_(2)S(aq)arrow FeS(s)+2NH_(4)Br(aq)
Write the net ionic equation for this reaction.

Solution
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Answer

Fe^{2+}(aq) + S^{2-}(aq) \rightarrow FeS(s) Explanation 1. Write the complete ionic equation Dissociate all aqueous compounds into ions: Fe^{2+}(aq) + 2Br^{-}(aq) + 2NH_{4}^{+}(aq) + S^{2-}(aq) \rightarrow FeS(s) + 2NH_{4}^{+}(aq) + 2Br^{-}(aq). 2. Identify and remove spectator ions Spectator ions are those that appear unchanged on both sides of the equation. Here, 2NH_{4}^{+}(aq) and 2Br^{-}(aq) are spectators. 3. Write the net ionic equation Remove spectator ions to focus on the actual chemical change: Fe^{2+}(aq) + S^{2-}(aq) \rightarrow FeS(s).

Explanation

1. Write the complete ionic equation<br /> Dissociate all aqueous compounds into ions: $Fe^{2+}(aq) + 2Br^{-}(aq) + 2NH_{4}^{+}(aq) + S^{2-}(aq) \rightarrow FeS(s) + 2NH_{4}^{+}(aq) + 2Br^{-}(aq)$.<br /><br />2. Identify and remove spectator ions<br /> Spectator ions are those that appear unchanged on both sides of the equation. Here, $2NH_{4}^{+}(aq)$ and $2Br^{-}(aq)$ are spectators.<br /><br />3. Write the net ionic equation<br /> Remove spectator ions to focus on the actual chemical change: $Fe^{2+}(aq) + S^{2-}(aq) \rightarrow FeS(s)$.
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