QuestionJune 13, 2025

Consider the following unbalanced equation: N_(2)(g)+H_(2)(g)arrow NH_(3)(g) How many moles of H_(2) will be required to react exactly with 3.83 mol N_(2) HOW DO WE GET THERE? What is the balanced equation for this reaction (in lowest multiple integers)? square N_(2)(g)+square H_(2)(g)arrow square NH_(3)(g)

Consider the following unbalanced equation: N_(2)(g)+H_(2)(g)arrow NH_(3)(g) How many moles of H_(2) will be required to react exactly with 3.83 mol N_(2) HOW DO WE GET THERE? What is the balanced equation for this reaction (in lowest multiple integers)? square N_(2)(g)+square H_(2)(g)arrow square NH_(3)(g)
Consider the following unbalanced equation:
N_(2)(g)+H_(2)(g)arrow NH_(3)(g)
How many moles of H_(2) will be required to react exactly with 3.83 mol N_(2)
HOW DO WE GET THERE?
What is the balanced equation for this reaction (in lowest multiple integers)?
square N_(2)(g)+square H_(2)(g)arrow square NH_(3)(g)

Solution
4.2(164 votes)

Answer

11.49 mol H_{2} Explanation 1. Balance the chemical equation The balanced equation is N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}(g). 2. Determine mole ratio from balanced equation From the balanced equation, 1 mole of N_{2} reacts with 3 moles of H_{2}. 3. Calculate moles of H_{2} needed Multiply the moles of N_{2} by the mole ratio: 3.83 \text{ mol } N_{2} \times \frac{3 \text{ mol } H_{2}}{1 \text{ mol } N_{2}} = 11.49 \text{ mol } H_{2}.

Explanation

1. Balance the chemical equation<br /> The balanced equation is $N_{2}(g) + 3H_{2}(g) \rightarrow 2NH_{3}(g)$.<br /><br />2. Determine mole ratio from balanced equation<br /> From the balanced equation, 1 mole of $N_{2}$ reacts with 3 moles of $H_{2}$.<br /><br />3. Calculate moles of $H_{2}$ needed<br /> Multiply the moles of $N_{2}$ by the mole ratio: $3.83 \text{ mol } N_{2} \times \frac{3 \text{ mol } H_{2}}{1 \text{ mol } N_{2}} = 11.49 \text{ mol } H_{2}$.
Click to rate:

Similar Questions