QuestionMay 26, 2025

Use the combined or ideal gas law to solve this problem. Round to 2 decimal places if needed (ex 3.1415926arrow 3.14) What pressure will be exerted by 0.450 moles of a gas at 25^circ C in a fixed container that has a volume of 650 mL? The pressure will be square latm

Use the combined or ideal gas law to solve this problem. Round to 2 decimal places if needed (ex 3.1415926arrow 3.14) What pressure will be exerted by 0.450 moles of a gas at 25^circ C in a fixed container that has a volume of 650 mL? The pressure will be square latm
Use the combined or ideal gas law to solve this problem. Round to 2 decimal places if needed (ex 3.1415926arrow 3.14) What pressure will be exerted by 0.450 moles of a gas at 25^circ C in a fixed container that has a volume of 650 mL? The pressure will be square latm

Solution
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Answer

16.96 atm Explanation 1. Convert temperature to Kelvin T(K) = 25 + 273.15 = 298.15 \, K 2. Convert volume to liters V(L) = 650 \, mL \times \frac{1 \, L}{1000 \, mL} = 0.65 \, L 3. Use the ideal gas law **PV = nRT** where R = 0.0821 \, \text{L atm/mol K} 4. Solve for pressure P P = \frac{nRT}{V} = \frac{0.450 \times 0.0821 \times 298.15}{0.65} 5. Calculate the pressure P \approx 16.96 \, \text{atm}

Explanation

1. Convert temperature to Kelvin<br /> $T(K) = 25 + 273.15 = 298.15 \, K$<br /><br />2. Convert volume to liters<br /> $V(L) = 650 \, mL \times \frac{1 \, L}{1000 \, mL} = 0.65 \, L$<br /><br />3. Use the ideal gas law<br /> **$PV = nRT$** where $R = 0.0821 \, \text{L atm/mol K}$<br /><br />4. Solve for pressure $P$<br /> $P = \frac{nRT}{V} = \frac{0.450 \times 0.0821 \times 298.15}{0.65}$<br /><br />5. Calculate the pressure<br /> $P \approx 16.96 \, \text{atm}$
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