QuestionApril 23, 2025

4NH_(3)+3O_(2)arrow 2N_(2)+6H_(2)O Identify the element that gets reduced. hydrogen nitrogen oxygen Identify the element that gets oxidized. nitrogen oxygen hydrogen

4NH_(3)+3O_(2)arrow 2N_(2)+6H_(2)O Identify the element that gets reduced. hydrogen nitrogen oxygen Identify the element that gets oxidized. nitrogen oxygen hydrogen
4NH_(3)+3O_(2)arrow 2N_(2)+6H_(2)O
Identify the element that gets reduced.
hydrogen
nitrogen
oxygen
Identify the element that gets oxidized.
nitrogen
oxygen
hydrogen

Solution
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Answer

Reduced: Nitrogen; Oxidized: Oxygen Explanation 1. Determine Oxidation States Calculate oxidation states for each element in reactants and products. In NH_3, nitrogen is -3, hydrogen is +1. In O_2, oxygen is 0. In N_2, nitrogen is 0. In H_2O, hydrogen is +1, oxygen is -2. 2. Identify Reduction Reduction involves a decrease in oxidation state. Nitrogen goes from -3 in NH_3 to 0 in N_2. Thus, nitrogen is reduced. 3. Identify Oxidation Oxidation involves an increase in oxidation state. Oxygen goes from 0 in O_2 to -2 in H_2O. Thus, oxygen is oxidized.

Explanation

1. Determine Oxidation States<br /> Calculate oxidation states for each element in reactants and products. In $NH_3$, nitrogen is -3, hydrogen is +1. In $O_2$, oxygen is 0. In $N_2$, nitrogen is 0. In $H_2O$, hydrogen is +1, oxygen is -2.<br /><br />2. Identify Reduction<br /> Reduction involves a decrease in oxidation state. Nitrogen goes from -3 in $NH_3$ to 0 in $N_2$. Thus, nitrogen is reduced.<br /><br />3. Identify Oxidation<br /> Oxidation involves an increase in oxidation state. Oxygen goes from 0 in $O_2$ to -2 in $H_2O$. Thus, oxygen is oxidized.
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