QuestionApril 21, 2025

When 1.25 g of a metal absorbs 87.4 J of heat, its temperature increases by 65.9^circ C What is the specific heat capacity of the metal? Select the correct answer below: 1.06(J)/(g^circ )C 1.66(J)/(g^circ )C 0.943(J)/(g^circ )C 0.603(J)/(g^circ )C

When 1.25 g of a metal absorbs 87.4 J of heat, its temperature increases by 65.9^circ C What is the specific heat capacity of the metal? Select the correct answer below: 1.06(J)/(g^circ )C 1.66(J)/(g^circ )C 0.943(J)/(g^circ )C 0.603(J)/(g^circ )C
When 1.25 g of a metal absorbs 87.4 J of heat, its temperature increases by 65.9^circ C What is the specific heat capacity of
the metal?
Select the correct answer below:
1.06(J)/(g^circ )C
1.66(J)/(g^circ )C
0.943(J)/(g^circ )C
0.603(J)/(g^circ )C

Solution
4.3(257 votes)

Answer

1.06\frac {J}{g^{\circ }C} Explanation 1. Identify the formula for specific heat capacity Use the formula **c = \frac{q}{m \cdot \Delta T}**, where c is specific heat capacity, q is heat absorbed, m is mass, and \Delta T is temperature change. 2. Substitute given values into the formula Given q = 87.4 \, J, m = 1.25 \, g, and \Delta T = 65.9^{\circ}C. Substitute these into the formula: c = \frac{87.4}{1.25 \times 65.9}. 3. Calculate the specific heat capacity Perform the calculation: c = \frac{87.4}{82.375} \approx 1.06 \, \frac{J}{g^{\circ}C}.

Explanation

1. Identify the formula for specific heat capacity<br /> Use the formula **$c = \frac{q}{m \cdot \Delta T}$**, where $c$ is specific heat capacity, $q$ is heat absorbed, $m$ is mass, and $\Delta T$ is temperature change.<br /><br />2. Substitute given values into the formula<br /> Given $q = 87.4 \, J$, $m = 1.25 \, g$, and $\Delta T = 65.9^{\circ}C$. Substitute these into the formula: $c = \frac{87.4}{1.25 \times 65.9}$.<br /><br />3. Calculate the specific heat capacity<br /> Perform the calculation: $c = \frac{87.4}{82.375} \approx 1.06 \, \frac{J}{g^{\circ}C}$.
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