QuestionAugust 24, 2025

needed for this question. The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25^circ C How many grams of testosterone, C_(19)H_(28)O_(2) a nonvolatile nonelectrolyte (MW=288.4g/mol) must be added to 256.9 grams of diethyl ether to reduce the vapor pressure to 458 .19 mm Hg? lethyl ether=CH_(3)CH_(2)OCH_(2)CH_(3)= 74.12g/mol Mass=square g

needed for this question. The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25^circ C How many grams of testosterone, C_(19)H_(28)O_(2) a nonvolatile nonelectrolyte (MW=288.4g/mol) must be added to 256.9 grams of diethyl ether to reduce the vapor pressure to 458 .19 mm Hg? lethyl ether=CH_(3)CH_(2)OCH_(2)CH_(3)= 74.12g/mol Mass=square g
needed for this question.
The vapor pressure of diethyl ether (ether)
is 463.57 mm Hg at 25^circ C
How many grams of testosterone,
C_(19)H_(28)O_(2) a nonvolatile nonelectrolyte
(MW=288.4g/mol) must be added to
256.9 grams of diethyl ether to reduce the
vapor pressure to 458 .19 mm Hg?
lethyl ether=CH_(3)CH_(2)OCH_(2)CH_(3)=
74.12g/mol
Mass=square g

Solution
4.4(229 votes)

Answer

6.89 g Explanation 1. Calculate the mole fraction of diethyl ether Use Raoult's Law: P_{\text{solution}} = X_{\text{ether}} \cdot P^0_{\text{ether}}. Rearrange to find X_{\text{ether}}: X_{\text{ether}} = \frac{P_{\text{solution}}}{P^0_{\text{ether}}} = \frac{458.19}{463.57}. 2. Calculate moles of diethyl ether Moles of ether = \frac{\text{mass}}{\text{molar mass}} = \frac{256.9}{74.12}. 3. Calculate moles of testosterone needed Use X_{\text{ether}} = \frac{\text{moles of ether}}{\text{moles of ether} + \text{moles of testosterone}} and solve for moles of testosterone. 4. Convert moles of testosterone to grams Grams = moles \times molar mass of testosterone (288.4 \, \text{g/mol}).

Explanation

1. Calculate the mole fraction of diethyl ether<br /> Use Raoult's Law: $P_{\text{solution}} = X_{\text{ether}} \cdot P^0_{\text{ether}}$. Rearrange to find $X_{\text{ether}}$: $X_{\text{ether}} = \frac{P_{\text{solution}}}{P^0_{\text{ether}}} = \frac{458.19}{463.57}$.<br /><br />2. Calculate moles of diethyl ether<br /> Moles of ether = $\frac{\text{mass}}{\text{molar mass}} = \frac{256.9}{74.12}$.<br /><br />3. Calculate moles of testosterone needed<br /> Use $X_{\text{ether}} = \frac{\text{moles of ether}}{\text{moles of ether} + \text{moles of testosterone}}$ and solve for moles of testosterone.<br /><br />4. Convert moles of testosterone to grams<br /> Grams = moles $\times$ molar mass of testosterone ($288.4 \, \text{g/mol}$).
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