QuestionApril 14, 2026

3. If 0.60 moles of iron sulfide react with 1.20 moles of oxygen, which is the limiting reactant? 4FeS+9O_(2)arrow 2Fe_(2)O_(3)+4SO_(3)

3. If 0.60 moles of iron sulfide react with 1.20 moles of oxygen, which is the limiting reactant? 4FeS+9O_(2)arrow 2Fe_(2)O_(3)+4SO_(3)
3. If 0.60 moles of iron sulfide react with 1.20 moles of oxygen, which is the limiting reactant?
4FeS+9O_(2)arrow 2Fe_(2)O_(3)+4SO_(3)

Solution
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Answer

Oxygen (O_2) is the limiting reactant. Explanation 1. Determine mole ratio from equation Reaction: 4FeS + 9O_2 \rightarrow 2Fe_2O_3 + 4SO_3 → FeS:O₂ ratio is 4:9. 2. Calculate required moles of O₂ for given FeS Required O_2 = 0.60 \ \text{mol FeS} \times \frac{9}{4} = 1.35 mol O₂. 3. Compare available moles to required Available O₂ = 1.20 mol < Required O₂ (1.35 mol) → O₂ is limiting.

Explanation

1. Determine mole ratio from equation <br /> Reaction: $4FeS + 9O_2 \rightarrow 2Fe_2O_3 + 4SO_3$ → FeS:O₂ ratio is $4:9$. <br /><br />2. Calculate required moles of O₂ for given FeS <br /> Required $O_2$ = $0.60 \ \text{mol FeS} \times \frac{9}{4} = 1.35$ mol O₂. <br /><br />3. Compare available moles to required <br /> Available O₂ = 1.20 mol < Required O₂ (1.35 mol) → O₂ is limiting.
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