QuestionAugust 24, 2025

2. angle JZQ=(9x+9)^circ and angle TLN=(8x+19)^circ

2. angle JZQ=(9x+9)^circ and angle TLN=(8x+19)^circ
2.
angle JZQ=(9x+9)^circ  and angle TLN=(8x+19)^circ

Solution
4.5(380 votes)

Answer

99^\circ Explanation 1. Set the equation for angles Since \angle JZQ and \angle TLN are equal, set 9x + 9 = 8x + 19. 2. Solve for x Subtract 8x from both sides: x + 9 = 19. Then subtract 9: x = 10. 3. Calculate angle measure Substitute x = 10 into either angle expression: \angle JZQ = 9(10) + 9 = 99^\circ.

Explanation

1. Set the equation for angles<br /> Since $\angle JZQ$ and $\angle TLN$ are equal, set $9x + 9 = 8x + 19$.<br />2. Solve for x<br /> Subtract $8x$ from both sides: $x + 9 = 19$. Then subtract 9: $x = 10$.<br />3. Calculate angle measure<br /> Substitute $x = 10$ into either angle expression: $\angle JZQ = 9(10) + 9 = 99^\circ$.
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