QuestionJuly 31, 2025

Consider the reaction of magnesium silicide with water shown below: Mg_(2)Si(s)+4H_(2)O(l)arrow 2Mg(OH)_(2)(aq)+SiH_(4)(g) In the reaction of 13.13 g Mg_(2)Si with excess water, 16.03 g Mg(OH)_(2) were produced. Calculate the percent yield of Mg(OH)_(2) Enter the answer rounded to 2 decimal places.Units are not necessary. Answer: square

Consider the reaction of magnesium silicide with water shown below: Mg_(2)Si(s)+4H_(2)O(l)arrow 2Mg(OH)_(2)(aq)+SiH_(4)(g) In the reaction of 13.13 g Mg_(2)Si with excess water, 16.03 g Mg(OH)_(2) were produced. Calculate the percent yield of Mg(OH)_(2) Enter the answer rounded to 2 decimal places.Units are not necessary. Answer: square
Consider the reaction of magnesium silicide with water shown below:
Mg_(2)Si(s)+4H_(2)O(l)arrow 2Mg(OH)_(2)(aq)+SiH_(4)(g)
In the reaction of 13.13 g Mg_(2)Si with excess water, 16.03 g Mg(OH)_(2) were produced. Calculate the percent yield of Mg(OH)_(2)
Enter the answer rounded to 2 decimal places.Units are not necessary.
Answer: square

Solution
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Answer

93.21 Explanation 1. Calculate moles of Mg_{2}Si Molar mass of Mg_{2}Si = 24.31 \times 2 + 28.09 = 76.63 g/mol. Moles of Mg_{2}Si = \frac{13.13}{76.63}. 2. Determine theoretical yield of Mg(OH)_{2} From the balanced equation, 1 mole of Mg_{2}Si produces 2 moles of Mg(OH)_{2}. Molar mass of Mg(OH)_{2} = 58.32 g/mol. Theoretical yield = moles of Mg_{2}Si \times 2 \times 58.32. 3. Calculate percent yield Percent yield = \left(\frac{\text{actual yield}}{\text{theoretical yield}}\right) \times 100, where actual yield is 16.03 g.

Explanation

1. Calculate moles of $Mg_{2}Si$<br /> Molar mass of $Mg_{2}Si = 24.31 \times 2 + 28.09 = 76.63$ g/mol. Moles of $Mg_{2}Si = \frac{13.13}{76.63}$.<br /><br />2. Determine theoretical yield of $Mg(OH)_{2}$<br /> From the balanced equation, 1 mole of $Mg_{2}Si$ produces 2 moles of $Mg(OH)_{2}$. Molar mass of $Mg(OH)_{2} = 58.32$ g/mol. Theoretical yield = moles of $Mg_{2}Si \times 2 \times 58.32$.<br /><br />3. Calculate percent yield<br /> Percent yield = $\left(\frac{\text{actual yield}}{\text{theoretical yield}}\right) \times 100$, where actual yield is 16.03 g.
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