QuestionMay 23, 2025

Which of the following ions does not have the same electron configuration as the noble gas neon? S^-2 Al^+3 0^-2 Mg^+2 F

Which of the following ions does not have the same electron configuration as the noble gas neon? S^-2 Al^+3 0^-2 Mg^+2 F
Which of the following ions does not have the same electron configuration as the noble gas neon? S^-2 Al^+3 0^-2 Mg^+2 F

Solution
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Answer

F Explanation 1. Determine Electron Configuration of Neon Neon has 10 electrons with configuration 1s^2 2s^2 2p^6. 2. Analyze Each Ion's Electron Configuration - \mathrm{S}^{-2}: Sulfur has 16 electrons, gains 2 to become 18 (1s^2 2s^2 2p^6 3s^2 3p^6). - \mathrm{Al}^{+3}: Aluminum has 13 electrons, loses 3 to become 10 (1s^2 2s^2 2p^6). - \mathrm{O}^{-2}: Oxygen has 8 electrons, gains 2 to become 10 (1s^2 2s^2 2p^6). - \mathrm{Mg}^{+2}: Magnesium has 12 electrons, loses 2 to become 10 (1s^2 2s^2 2p^6). - F: Fluorine has 9 electrons (1s^2 2s^2 2p^5). 3. Identify the Ion Not Matching Neon Compare each ion's electron configuration to Neon's. Only F does not match.

Explanation

1. Determine Electron Configuration of Neon<br /> Neon has 10 electrons with configuration $1s^2 2s^2 2p^6$.<br /><br />2. Analyze Each Ion's Electron Configuration<br /> - $\mathrm{S}^{-2}$: Sulfur has 16 electrons, gains 2 to become 18 ($1s^2 2s^2 2p^6 3s^2 3p^6$).<br /> - $\mathrm{Al}^{+3}$: Aluminum has 13 electrons, loses 3 to become 10 ($1s^2 2s^2 2p^6$).<br /> - $\mathrm{O}^{-2}$: Oxygen has 8 electrons, gains 2 to become 10 ($1s^2 2s^2 2p^6$).<br /> - $\mathrm{Mg}^{+2}$: Magnesium has 12 electrons, loses 2 to become 10 ($1s^2 2s^2 2p^6$).<br /> - F: Fluorine has 9 electrons ($1s^2 2s^2 2p^5$).<br /><br />3. Identify the Ion Not Matching Neon<br /> Compare each ion's electron configuration to Neon's. Only F does not match.
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