QuestionApril 25, 2025

What is the solubility product expression for Al(OH)_(3) A K_(sp)=[Al^3+][3OH^-] B K_(sp)=3[Al^3+][OH^-]^3 C K_(sp)=[Al^3+][OH^-]^3 D K_(sp)=[Al^3+][3OH^-]^3 E K_(sp)=[Al^3+][OH^-]

What is the solubility product expression for Al(OH)_(3) A K_(sp)=[Al^3+][3OH^-] B K_(sp)=3[Al^3+][OH^-]^3 C K_(sp)=[Al^3+][OH^-]^3 D K_(sp)=[Al^3+][3OH^-]^3 E K_(sp)=[Al^3+][OH^-]
What is the solubility product expression for Al(OH)_(3)
A K_(sp)=[Al^3+][3OH^-]
B K_(sp)=3[Al^3+][OH^-]^3
C K_(sp)=[Al^3+][OH^-]^3
D K_(sp)=[Al^3+][3OH^-]^3
E K_(sp)=[Al^3+][OH^-]

Solution
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Answer

C K_{sp}=[Al^{3+}][OH^{-}]^{3} Explanation 1. Write the dissociation equation Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^{-} 2. Apply the solubility product expression **K_{sp} = [Al^{3+}][OH^{-}]^3** based on the stoichiometry of the dissociation.

Explanation

1. Write the dissociation equation<br /> $Al(OH)_3 \rightleftharpoons Al^{3+} + 3OH^{-}$<br /><br />2. Apply the solubility product expression<br /> **$K_{sp} = [Al^{3+}][OH^{-}]^3$** based on the stoichiometry of the dissociation.
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