QuestionMay 26, 2025

18. Determine the total pressure of a gas mixture that contains O_(2),N_(2) and He, if the partial pressure of the gases ares P_((O_(2)))=200mmHg,P_((N2))=350mmHg,P_((NO2))=428mmHg 975 grams 1.0 atm 975 mm Hg 975 kPa

18. Determine the total pressure of a gas mixture that contains O_(2),N_(2) and He, if the partial pressure of the gases ares P_((O_(2)))=200mmHg,P_((N2))=350mmHg,P_((NO2))=428mmHg 975 grams 1.0 atm 975 mm Hg 975 kPa
18. Determine the total pressure of a gas mixture that contains O_(2),N_(2) and He, if the partial pressure of the gases ares P_((O_(2)))=200mmHg,P_((N2))=350mmHg,P_((NO2))=428mmHg 975 grams 1.0 atm 975 mm Hg 975 kPa

Solution
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Answer

978 mm Hg Explanation 1. Identify Partial Pressures The partial pressures given are P_{(O_2)} = 200 \, \text{mmHg}, P_{(N_2)} = 350 \, \text{mmHg}, and P_{(NO_2)} = 428 \, \text{mmHg}. 2. Apply Dalton's Law of Partial Pressures **Dalton's Law** states that the total pressure of a gas mixture is the sum of the partial pressures of each individual gas. Therefore, calculate the total pressure as follows: \[ P_{\text{total}} = P_{(O_2)} + P_{(N_2)} + P_{(NO_2)} \] 3. Calculate Total Pressure Substitute the values into the formula: \[ P_{\text{total}} = 200 \, \text{mmHg} + 350 \, \text{mmHg} + 428 \, \text{mmHg} = 978 \, \text{mmHg} \]

Explanation

1. Identify Partial Pressures<br /> The partial pressures given are $P_{(O_2)} = 200 \, \text{mmHg}$, $P_{(N_2)} = 350 \, \text{mmHg}$, and $P_{(NO_2)} = 428 \, \text{mmHg}$.<br /><br />2. Apply Dalton's Law of Partial Pressures<br /> **Dalton's Law** states that the total pressure of a gas mixture is the sum of the partial pressures of each individual gas. Therefore, calculate the total pressure as follows:<br />\[ P_{\text{total}} = P_{(O_2)} + P_{(N_2)} + P_{(NO_2)} \]<br /><br />3. Calculate Total Pressure<br /> Substitute the values into the formula:<br />\[ P_{\text{total}} = 200 \, \text{mmHg} + 350 \, \text{mmHg} + 428 \, \text{mmHg} = 978 \, \text{mmHg} \]
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