QuestionJune 12, 2025

14. What is the concentration of H_(3)O^+ ions in the 0 .003 M H_(2)SO_(4) solution? What is the pH of this solution?

14. What is the concentration of H_(3)O^+ ions in the 0 .003 M H_(2)SO_(4) solution? What is the pH of this solution?
14. What is the concentration of H_(3)O^+ ions in the 0 .003 M H_(2)SO_(4) solution? What is
the pH of this solution?

Solution
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Answer

The concentration of \mathrm{H}_{3} \mathrm{O}^{+} ions is 0.006 \mathrm{M} . The pH of the solution is approximately 2.22 . Explanation 1. Determine ionization of \mathrm{H}_{2} \mathrm{SO}_{4} \mathrm{H}_{2} \mathrm{SO}_{4} is a strong acid and dissociates completely in water. It produces 2 moles of \mathrm{H}_{3} \mathrm{O}^{+} ions per mole of \mathrm{H}_{2} \mathrm{SO}_{4} . 2. Calculate concentration of \mathrm{H}_{3} \mathrm{O}^{+} Concentration of \mathrm{H}_{3} \mathrm{O}^{+} = 2 \times 0.003 \mathrm{M} = 0.006 \mathrm{M} . 3. Calculate pH **pH = -\log[\mathrm{H}_{3} \mathrm{O}^{+}]**. Substitute [\mathrm{H}_{3} \mathrm{O}^{+}] = 0.006 \mathrm{M} into the formula: \text{pH} = -\log(0.006) .

Explanation

1. Determine ionization of $ \mathrm{H}_{2} \mathrm{SO}_{4} $<br /> $ \mathrm{H}_{2} \mathrm{SO}_{4} $ is a strong acid and dissociates completely in water. It produces 2 moles of $ \mathrm{H}_{3} \mathrm{O}^{+} $ ions per mole of $ \mathrm{H}_{2} \mathrm{SO}_{4} $.<br />2. Calculate concentration of $ \mathrm{H}_{3} \mathrm{O}^{+} $<br /> Concentration of $ \mathrm{H}_{3} \mathrm{O}^{+} $ = $ 2 \times 0.003 \mathrm{M} = 0.006 \mathrm{M} $.<br />3. Calculate pH<br /> **pH = -\log[\mathrm{H}_{3} \mathrm{O}^{+}]**. Substitute $ [\mathrm{H}_{3} \mathrm{O}^{+}] = 0.006 \mathrm{M} $ into the formula: $ \text{pH} = -\log(0.006) $.
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