QuestionMay 27, 2025

How many molecules are in 2.41 grams of KOH?

How many molecules are in 2.41 grams of KOH?
How many molecules are in
2.41 grams of KOH?

Solution
4.6(153 votes)

Answer

Approximately 2.58 \times 10^{22} molecules of KOH. Explanation 1. Calculate moles of KOH Use the formula: **moles = \frac{\text{mass}}{\text{molar mass}}**. The molar mass of KOH is approximately 56.11 g/mol. So, moles of KOH = \frac{2.41}{56.11}. 2. Calculate molecules using Avogadro's number Multiply the moles by Avogadro's number (approximately 6.022 \times 10^{23} molecules/mol) to find the number of molecules.

Explanation

1. Calculate moles of KOH<br /> Use the formula: **moles = \frac{\text{mass}}{\text{molar mass}}**. The molar mass of KOH is approximately 56.11 g/mol. So, moles of KOH = $\frac{2.41}{56.11}$.<br />2. Calculate molecules using Avogadro's number<br /> Multiply the moles by Avogadro's number (approximately $6.022 \times 10^{23}$ molecules/mol) to find the number of molecules.
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