QuestionMay 28, 2025

Using the following reaction: Fe_(2)O_(3)+3Mg(OH)_(2)- gt 2Fe(OH)_(3)+3MgO How many mols of Fe_(2)O_(3) are required to make 131.1 g Fe(OH)_(3) square

Using the following reaction: Fe_(2)O_(3)+3Mg(OH)_(2)- gt 2Fe(OH)_(3)+3MgO How many mols of Fe_(2)O_(3) are required to make 131.1 g Fe(OH)_(3) square
Using the following reaction:
Fe_(2)O_(3)+3Mg(OH)_(2)- gt 2Fe(OH)_(3)+3MgO
How many mols of Fe_(2)O_(3) are required to make 131.1 g Fe(OH)_(3)
square

Solution
4.1(322 votes)

Answer

0.613 \, mol \, Fe_2O_3 Explanation 1. Calculate moles of Fe(OH)_3 Molar mass of Fe(OH)_3 is 55.85 + 3 \times (16 + 1) = 106.87 \, g/mol. Moles of Fe(OH)_3 = \frac{131.1}{106.87}. 2. Use stoichiometry to find moles of Fe_2O_3 From the balanced equation, 2 \, mol \, Fe(OH)_3 corresponds to 1 \, mol \, Fe_2O_3. Therefore, moles of Fe_2O_3 = \frac{\text{moles of } Fe(OH)_3}{2}.

Explanation

1. Calculate moles of $Fe(OH)_3$<br /> Molar mass of $Fe(OH)_3$ is $55.85 + 3 \times (16 + 1) = 106.87 \, g/mol$. Moles of $Fe(OH)_3 = \frac{131.1}{106.87}$.<br />2. Use stoichiometry to find moles of $Fe_2O_3$<br /> From the balanced equation, $2 \, mol \, Fe(OH)_3$ corresponds to $1 \, mol \, Fe_2O_3$. Therefore, moles of $Fe_2O_3 = \frac{\text{moles of } Fe(OH)_3}{2}$.
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