QuestionAugust 8, 2025

3. Determine the molecular formula to which the following empirical formulas and molar masses pertain: a) SNH(188.35g/mol) b) CoC_(4)O_(4)(341.94g/mol)

3. Determine the molecular formula to which the following empirical formulas and molar masses pertain: a) SNH(188.35g/mol) b) CoC_(4)O_(4)(341.94g/mol)
3. Determine the molecular formula to which the following empirical formulas and molar masses
pertain:
a) SNH(188.35g/mol)
b) CoC_(4)O_(4)(341.94g/mol)

Solution
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Answer

a) S_4N_4H_4 ### b) Co_2C_8O_8 Explanation 1. Calculate the empirical formula mass for SNH Add atomic masses: S = 32.07 \, \text{g/mol}, N = 14.01 \, \text{g/mol}, H = 1.01 \, \text{g/mol}. Total: 32.07 + 14.01 + 1.01 = 47.09 \, \text{g/mol}. 2. Determine the molecular formula for SNH Divide molar mass by empirical formula mass: \frac{188.35}{47.09} \approx 4. Multiply subscripts in SNH by 4 to get S_4N_4H_4. 3. Calculate the empirical formula mass for CoC_{4}O_{4} Add atomic masses: Co = 58.93 \, \text{g/mol}, C = 12.01 \, \text{g/mol}, O = 16.00 \, \text{g/mol}. Total: 58.93 + (4 \times 12.01) + (4 \times 16.00) = 170.93 \, \text{g/mol}. 4. Determine the molecular formula for CoC_{4}O_{4} Divide molar mass by empirical formula mass: \frac{341.94}{170.93} \approx 2. Multiply subscripts in CoC_{4}O_{4} by 2 to get Co_2C_8O_8.

Explanation

1. Calculate the empirical formula mass for $SNH$<br /> Add atomic masses: $S = 32.07 \, \text{g/mol}$, $N = 14.01 \, \text{g/mol}$, $H = 1.01 \, \text{g/mol}$. Total: $32.07 + 14.01 + 1.01 = 47.09 \, \text{g/mol}$.<br /><br />2. Determine the molecular formula for $SNH$<br /> Divide molar mass by empirical formula mass: $\frac{188.35}{47.09} \approx 4$. Multiply subscripts in $SNH$ by 4 to get $S_4N_4H_4$.<br /><br />3. Calculate the empirical formula mass for $CoC_{4}O_{4}$<br /> Add atomic masses: $Co = 58.93 \, \text{g/mol}$, $C = 12.01 \, \text{g/mol}$, $O = 16.00 \, \text{g/mol}$. Total: $58.93 + (4 \times 12.01) + (4 \times 16.00) = 170.93 \, \text{g/mol}$.<br /><br />4. Determine the molecular formula for $CoC_{4}O_{4}$<br /> Divide molar mass by empirical formula mass: $\frac{341.94}{170.93} \approx 2$. Multiply subscripts in $CoC_{4}O_{4}$ by 2 to get $Co_2C_8O_8$.
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