QuestionMay 26, 2025

How many moles of Na_(2)CO_(3) are needed to react with 750 mL of 0.250 M H_(2)SO_(4) solution? Na_(2)CO_(3)+H_(2)SO_(4)arrow Na_(2)SO_(4)+CO_(2)+H_(2)O 3.00times 10^3 0.333 1.33 0.188

How many moles of Na_(2)CO_(3) are needed to react with 750 mL of 0.250 M H_(2)SO_(4) solution? Na_(2)CO_(3)+H_(2)SO_(4)arrow Na_(2)SO_(4)+CO_(2)+H_(2)O 3.00times 10^3 0.333 1.33 0.188
How many moles of Na_(2)CO_(3) are needed to react with 750 mL of 0.250 M H_(2)SO_(4) solution?
Na_(2)CO_(3)+H_(2)SO_(4)arrow Na_(2)SO_(4)+CO_(2)+H_(2)O
3.00times 10^3
0.333
1.33
0.188

Solution
4.6(277 votes)

Answer

0.188 Explanation 1. Calculate moles of H_{2}SO_{4} Use the formula **n = C \times V** where C = 0.250 \, M and V = 0.750 \, L. Thus, n = 0.250 \times 0.750 = 0.1875 moles. 2. Determine mole ratio from balanced equation The balanced equation shows a 1:1 mole ratio between Na_{2}CO_{3} and H_{2}SO_{4}. 3. Calculate moles of Na_{2}CO_{3} Since the ratio is 1:1, moles of Na_{2}CO_{3} needed = moles of H_{2}SO_{4} = 0.1875 moles.

Explanation

1. Calculate moles of $H_{2}SO_{4}$<br /> Use the formula **$n = C \times V$** where $C = 0.250 \, M$ and $V = 0.750 \, L$. Thus, $n = 0.250 \times 0.750 = 0.1875$ moles.<br />2. Determine mole ratio from balanced equation<br /> The balanced equation shows a 1:1 mole ratio between $Na_{2}CO_{3}$ and $H_{2}SO_{4}$.<br />3. Calculate moles of $Na_{2}CO_{3}$<br /> Since the ratio is 1:1, moles of $Na_{2}CO_{3}$ needed = moles of $H_{2}SO_{4}$ = 0.1875 moles.
Click to rate:

Similar Questions