QuestionJuly 11, 2025

What mass in grams of magnesium chloride can be produced from 4.37 mol of chlorine gas reacting with excess magnesium? Mg(s)+Cl_(2)(g)arrow MgCI_(2)(s) Mg(s)+Cl_(2)(g)leftharpoons MgCl_(2)(s)

What mass in grams of magnesium chloride can be produced from 4.37 mol of chlorine gas reacting with excess magnesium? Mg(s)+Cl_(2)(g)arrow MgCI_(2)(s) Mg(s)+Cl_(2)(g)leftharpoons MgCl_(2)(s)
What mass in grams of magnesium chloride can be produced
from 4.37 mol of chlorine gas reacting with excess
magnesium?
Mg(s)+Cl_(2)(g)arrow MgCI_(2)(s)
Mg(s)+Cl_(2)(g)leftharpoons MgCl_(2)(s)

Solution
4.1(148 votes)

Answer

416.06 grams of MgCl_2 can be produced. Explanation 1. Determine the molar ratio From the balanced equation Mg(s) + Cl_2(g) \rightarrow MgCl_2(s), 1 mole of Cl_2 produces 1 mole of MgCl_2. 2. Calculate moles of MgCl_2 Since 4.37 mol of Cl_2 is used, it will produce 4.37 mol of MgCl_2. 3. Calculate mass of MgCl_2 Molar mass of MgCl_2 = 24.31 \, (Mg) + 2 \times 35.45 \, (Cl) = 95.21 \, g/mol. Mass = moles \times molar mass = 4.37 \, \text{mol} \times 95.21 \, \text{g/mol}.

Explanation

1. Determine the molar ratio<br /> From the balanced equation $Mg(s) + Cl_2(g) \rightarrow MgCl_2(s)$, 1 mole of $Cl_2$ produces 1 mole of $MgCl_2$.<br /><br />2. Calculate moles of $MgCl_2$<br /> Since 4.37 mol of $Cl_2$ is used, it will produce 4.37 mol of $MgCl_2$.<br /><br />3. Calculate mass of $MgCl_2$<br /> Molar mass of $MgCl_2 = 24.31 \, (Mg) + 2 \times 35.45 \, (Cl) = 95.21 \, g/mol$. Mass = moles $\times$ molar mass = $4.37 \, \text{mol} \times 95.21 \, \text{g/mol}$.
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