QuestionJune 11, 2025

1) A sample of argon gas has a temperature of 402 K and a pressure of 6.8 atm. What will the temperature be if th pressure is decreased to 2.5 atm?

1) A sample of argon gas has a temperature of 402 K and a pressure of 6.8 atm. What will the temperature be if th pressure is decreased to 2.5 atm?
1) A sample of argon gas has a temperature of 402 K and a pressure of 6.8 atm. What will the
temperature be if th pressure is decreased to 2.5 atm?

Solution
4.3(182 votes)

Answer

147.79 K Explanation 1. Identify the Gas Law Use the **ideal gas law** in the form of **Gay-Lussac's Law** for constant volume: \frac{P_1}{T_1} = \frac{P_2}{T_2}. 2. Substitute Known Values P_1 = 6.8 atm, T_1 = 402 K, P_2 = 2.5 atm. Substitute these into the formula: \frac{6.8}{402} = \frac{2.5}{T_2}. 3. Solve for T_2 Rearrange to find T_2: T_2 = \frac{2.5 \times 402}{6.8}. 4. Calculate Compute T_2: T_2 = \frac{1005}{6.8} \approx 147.79 K.

Explanation

1. Identify the Gas Law<br /> Use the **ideal gas law** in the form of **Gay-Lussac's Law** for constant volume: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$.<br /><br />2. Substitute Known Values<br /> $P_1 = 6.8$ atm, $T_1 = 402$ K, $P_2 = 2.5$ atm. Substitute these into the formula: $\frac{6.8}{402} = \frac{2.5}{T_2}$.<br /><br />3. Solve for $T_2$<br /> Rearrange to find $T_2$: $T_2 = \frac{2.5 \times 402}{6.8}$.<br /><br />4. Calculate<br /> Compute $T_2$: $T_2 = \frac{1005}{6.8} \approx 147.79$ K.
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