QuestionJune 12, 2025

Equations Write a chemical equation for each of the following combinations of known solutions. Balance each equation. Use the symbol (s) after each insoluble compound and (aq) after each soluble one. HCl(aq)+Pb(NO_(3))_(2)(aq)arrow NaOH(aq)+Co(NO_(3))_(2)(aq)arrow K_(2)SO_(4)(aq)+BaCl_(2)(aq)arrow Pb(NO_(3))_(2)(aq)+BaCl_(2)(aq)arrow

Equations Write a chemical equation for each of the following combinations of known solutions. Balance each equation. Use the symbol (s) after each insoluble compound and (aq) after each soluble one. HCl(aq)+Pb(NO_(3))_(2)(aq)arrow NaOH(aq)+Co(NO_(3))_(2)(aq)arrow K_(2)SO_(4)(aq)+BaCl_(2)(aq)arrow Pb(NO_(3))_(2)(aq)+BaCl_(2)(aq)arrow
Equations
Write a chemical equation for each of the following combinations of known solutions. Balance each
equation. Use the symbol (s) after each insoluble compound and (aq) after each soluble one.
HCl(aq)+Pb(NO_(3))_(2)(aq)arrow 
NaOH(aq)+Co(NO_(3))_(2)(aq)arrow 
K_(2)SO_(4)(aq)+BaCl_(2)(aq)arrow 
Pb(NO_(3))_(2)(aq)+BaCl_(2)(aq)arrow

Solution
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Answer

2HCl(aq) + Pb(NO_{3})_{2}(aq) \rightarrow PbCl_{2}(s) + 2HNO_{3}(aq) ### 2NaOH(aq) + Co(NO_{3})_{2}(aq) \rightarrow Co(OH)_{2}(s) + 2NaNO_{3}(aq) ### K_{2}SO_{4}(aq) + BaCl_{2}(aq) \rightarrow BaSO_{4}(s) + 2KCl(aq) ### Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq) \rightarrow Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq) Explanation 1. Write the chemical equation for HCl(aq) + Pb(NO_{3})_{2}(aq) The products are PbCl_2(s) and HNO_3(aq). The balanced equation is: 2HCl(aq) + Pb(NO_{3})_{2}(aq) \rightarrow PbCl_{2}(s) + 2HNO_{3}(aq) 2. Write the chemical equation for NaOH(aq) + Co(NO_{3})_{2}(aq) The products are Co(OH)_2(s) and NaNO_3(aq). The balanced equation is: 2NaOH(aq) + Co(NO_{3})_{2}(aq) \rightarrow Co(OH)_{2}(s) + 2NaNO_{3}(aq) 3. Write the chemical equation for K_{2}SO_{4}(aq) + BaCl_{2}(aq) The products are BaSO_4(s) and KCl(aq). The balanced equation is: K_{2}SO_{4}(aq) + BaCl_{2}(aq) \rightarrow BaSO_{4}(s) + 2KCl(aq) 4. Write the chemical equation for Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq) No reaction occurs as all possible products are soluble. The equation remains: Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq) \rightarrow Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq)

Explanation

1. Write the chemical equation for $HCl(aq) + Pb(NO_{3})_{2}(aq)$<br /> The products are $PbCl_2(s)$ and $HNO_3(aq)$. The balanced equation is:<br /> $2HCl(aq) + Pb(NO_{3})_{2}(aq) \rightarrow PbCl_{2}(s) + 2HNO_{3}(aq)$<br /><br />2. Write the chemical equation for $NaOH(aq) + Co(NO_{3})_{2}(aq)$<br /> The products are $Co(OH)_2(s)$ and $NaNO_3(aq)$. The balanced equation is:<br /> $2NaOH(aq) + Co(NO_{3})_{2}(aq) \rightarrow Co(OH)_{2}(s) + 2NaNO_{3}(aq)$<br /><br />3. Write the chemical equation for $K_{2}SO_{4}(aq) + BaCl_{2}(aq)$<br /> The products are $BaSO_4(s)$ and $KCl(aq)$. The balanced equation is:<br /> $K_{2}SO_{4}(aq) + BaCl_{2}(aq) \rightarrow BaSO_{4}(s) + 2KCl(aq)$<br /><br />4. Write the chemical equation for $Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq)$<br /> No reaction occurs as all possible products are soluble. The equation remains:<br /> $Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq) \rightarrow Pb(NO_{3})_{2}(aq) + BaCl_{2}(aq)$
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