QuestionJuly 29, 2025

Based on the activity series provided, which reactants will form products? Fgt Clgt Brgt I Cu_(2)+Br_(2)arrow Cl_(2)+AlF_(3)arrow Br_(2)+NaClarrow CuF_(2)+I_(2)arrow

Based on the activity series provided, which reactants will form products? Fgt Clgt Brgt I Cu_(2)+Br_(2)arrow Cl_(2)+AlF_(3)arrow Br_(2)+NaClarrow CuF_(2)+I_(2)arrow
Based on the activity series provided, which reactants will form products?
Fgt Clgt Brgt I
Cu_(2)+Br_(2)arrow 
Cl_(2)+AlF_(3)arrow 
Br_(2)+NaClarrow 
CuF_(2)+I_(2)arrow

Solution
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Answer

None of the reactants will form products. Explanation 1. Determine Reactivity Compare the reactivity of halogens in each reaction using the activity series F > Cl > Br > I. 2. Analyze Reaction 1 (Cu_{2}+Br_{2}) Copper is not reactive enough to displace bromine. No reaction occurs. 3. Analyze Reaction 2 (Cl_{2}+AlF_{3}) Chlorine cannot displace fluorine because fluorine is more reactive. No reaction occurs. 4. Analyze Reaction 3 (Br_{2}+NaCl) Bromine cannot displace chlorine because chlorine is more reactive. No reaction occurs. 5. Analyze Reaction 4 (CuF_{2}+I_{2}) Iodine cannot displace fluorine because fluorine is more reactive. No reaction occurs.

Explanation

1. Determine Reactivity<br /> Compare the reactivity of halogens in each reaction using the activity series $F > Cl > Br > I$.<br /><br />2. Analyze Reaction 1 ($Cu_{2}+Br_{2}$)<br /> Copper is not reactive enough to displace bromine. No reaction occurs.<br /><br />3. Analyze Reaction 2 ($Cl_{2}+AlF_{3}$)<br /> Chlorine cannot displace fluorine because fluorine is more reactive. No reaction occurs.<br /><br />4. Analyze Reaction 3 ($Br_{2}+NaCl$)<br /> Bromine cannot displace chlorine because chlorine is more reactive. No reaction occurs.<br /><br />5. Analyze Reaction 4 ($CuF_{2}+I_{2}$)<br /> Iodine cannot displace fluorine because fluorine is more reactive. No reaction occurs.
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