QuestionAugust 25, 2025

In Exercises 19-24, solve the equation Determine whether the equation has one solution, no solution . or infinitely many solutions (See Example 3.) 19. 3t+4=12+3t 20. 6d+8=14+3d 21. 2(h+1)=5h-7 22. 12y+6=6(2y+1) 23 3(4g+6)=2(6g+9) 24 5(1+2m)=(1)/(2)(8+20m) ERROR ANALYSIS In Exercises 25 and 26.describe and correct the error in solving the equation. 25. 5c-6=4-3c 2c-6=4 2c=10 c=5

In Exercises 19-24, solve the equation Determine whether the equation has one solution, no solution . or infinitely many solutions (See Example 3.) 19. 3t+4=12+3t 20. 6d+8=14+3d 21. 2(h+1)=5h-7 22. 12y+6=6(2y+1) 23 3(4g+6)=2(6g+9) 24 5(1+2m)=(1)/(2)(8+20m) ERROR ANALYSIS In Exercises 25 and 26.describe and correct the error in solving the equation. 25. 5c-6=4-3c 2c-6=4 2c=10 c=5
In Exercises 19-24, solve the equation Determine
whether the equation has one solution, no solution . or
infinitely many solutions (See Example 3.)
19. 3t+4=12+3t
20. 6d+8=14+3d
21. 2(h+1)=5h-7
22. 12y+6=6(2y+1)
23 3(4g+6)=2(6g+9)
24 5(1+2m)=(1)/(2)(8+20m)
ERROR ANALYSIS In Exercises 25 and 26.describe and
correct the error in solving the equation.
25.
5c-6=4-3c
2c-6=4
2c=10
c=5

Solution
4.1(131 votes)

Answer

1. Simplify the equation ### For each equation, simplify both sides if necessary. ## Step2: Compare coefficients ### Determine if the simplified equation results in a contradiction, identity, or a single solution. ## Step3: Solve for the variable ### If applicable, solve for the variable using algebraic manipulation. # Answer: ### 19. Infinitely many solutions (both sides are equal). ### 20. One solution: d = 2. ### 21. One solution: h = 3. ### 22. Infinitely many solutions (both sides are equal). ### 23. No solution (results in a contradiction). ### 24. Infinitely many solutions (both sides are equal). # Error Analysis: ## Step1: Identify the error ### The error is in combining terms incorrectly. ## Step2: Correct the error ### Correctly combine like terms: 5c - 6 = 4 - 3c becomes 8c = 10. # Answer: ### Correct solution: c = \frac{5}{4}.
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