QuestionApril 20, 2025

Balance the following chemical equation (if necessary): C_(6)H_(6)(l)+O_(2)(g)arrow H_(2)O(g)+CO_(2)(g)

Balance the following chemical equation (if necessary): C_(6)H_(6)(l)+O_(2)(g)arrow H_(2)O(g)+CO_(2)(g)
Balance the following chemical equation (if necessary):
C_(6)H_(6)(l)+O_(2)(g)arrow H_(2)O(g)+CO_(2)(g)

Solution
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Answer

2C_6H_6(l) + 15O_2(g) \rightarrow 6H_2O(g) + 12CO_2(g) Explanation 1. Identify the number of atoms Count atoms for each element in reactants and products. - Reactants: C_6H_6: 6 C, 6 H; O_2: 2 O - Products: H_2O: 2 H, 1 O; CO_2: 1 C, 2 O 2. Balance carbon atoms Ensure equal carbon atoms on both sides. - Place coefficient 6 before CO_2: C_6H_6 + O_2 \rightarrow H_2O + 6CO_2 3. Balance hydrogen atoms Ensure equal hydrogen atoms on both sides. - Place coefficient 3 before H_2O: C_6H_6 + O_2 \rightarrow 3H_2O + 6CO_2 4. Balance oxygen atoms Ensure equal oxygen atoms on both sides. - Total O in products: 3 \times 1 + 6 \times 2 = 15 - Place coefficient 7.5 before O_2: C_6H_6 + 7.5O_2 \rightarrow 3H_2O + 6CO_2 5. Adjust coefficients to whole numbers Multiply entire equation by 2 to eliminate fraction. - 2C_6H_6 + 15O_2 \rightarrow 6H_2O + 12CO_2

Explanation

1. Identify the number of atoms<br /> Count atoms for each element in reactants and products.<br />- Reactants: $C_6H_6$: 6 C, 6 H; $O_2$: 2 O<br />- Products: $H_2O$: 2 H, 1 O; $CO_2$: 1 C, 2 O<br /><br />2. Balance carbon atoms<br /> Ensure equal carbon atoms on both sides.<br />- Place coefficient 6 before $CO_2$: $C_6H_6 + O_2 \rightarrow H_2O + 6CO_2$<br /><br />3. Balance hydrogen atoms<br /> Ensure equal hydrogen atoms on both sides.<br />- Place coefficient 3 before $H_2O$: $C_6H_6 + O_2 \rightarrow 3H_2O + 6CO_2$<br /><br />4. Balance oxygen atoms<br /> Ensure equal oxygen atoms on both sides.<br />- Total O in products: $3 \times 1 + 6 \times 2 = 15$<br />- Place coefficient 7.5 before $O_2$: $C_6H_6 + 7.5O_2 \rightarrow 3H_2O + 6CO_2$<br /><br />5. Adjust coefficients to whole numbers<br /> Multiply entire equation by 2 to eliminate fraction.<br />- $2C_6H_6 + 15O_2 \rightarrow 6H_2O + 12CO_2$
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