QuestionMarch 10, 2026

Calculate how many atoms of each element are present in the following compounds. 1. NaHCO_(3) 2. C_(2)H_(4)O_(2) 3. Mg(OH)_(2) 4. 3H_(3)PO_(4) 5. 2H_(2)SO_(4)

Calculate how many atoms of each element are present in the following compounds. 1. NaHCO_(3) 2. C_(2)H_(4)O_(2) 3. Mg(OH)_(2) 4. 3H_(3)PO_(4) 5. 2H_(2)SO_(4)
Calculate how many atoms of each element are present in the following compounds. 1. NaHCO_(3) 2. C_(2)H_(4)O_(2) 3. Mg(OH)_(2) 4. 3H_(3)PO_(4) 5. 2H_(2)SO_(4)

Solution
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Answer

1. Na: 1, H: 1, C: 1, O: 3 ### 2. C: 2, H: 4, O: 2 ### 3. Mg: 1, O: 2, H: 2 ### 4. H: 9, P: 3, O: 12 ### 5. H: 4, S: 2, O: 8 Explanation 1. Identify subscripts and multipliers Subscripts indicate atoms per molecule, parentheses and coefficients multiply totals. 2. Calculate atoms for each compound **1. NaHCO_3:** Na: 1, H: 1, C: 1, O: 3 **2. C_2H_4O_2:** C: 2, H: 4, O: 2 **3. Mg(OH)_2:** Mg: 1, O: 2\times1=2, H: 2\times1=2 **4. 3H_3PO_4:** Per molecule: H: 3, P: 1, O: 4 Multiply by 3: H: 3\times3=9, P: 3\times1=3, O: 3\times4=12 **5. 2H_2SO_4:** Per molecule: H: 2, S: 1, O: 4 Multiply by 2: H: 2\times2=4, S: 2\times1=2, O: 2\times4=8

Explanation

1. Identify subscripts and multipliers <br /> Subscripts indicate atoms per molecule, parentheses and coefficients multiply totals. <br /><br />2. Calculate atoms for each compound <br /> **1. $NaHCO_3$:**<br />Na: 1, H: 1, C: 1, O: 3 <br /><br /> **2. $C_2H_4O_2$:**<br />C: 2, H: 4, O: 2 <br /><br /> **3. $Mg(OH)_2$:**<br />Mg: 1, O: $2\times1=2$, H: $2\times1=2$ <br /><br /> **4. $3H_3PO_4$:**<br />Per molecule: H: 3, P: 1, O: 4 <br />Multiply by 3: H: $3\times3=9$, P: $3\times1=3$, O: $3\times4=12$ <br /><br /> **5. $2H_2SO_4$:**<br />Per molecule: H: 2, S: 1, O: 4 <br />Multiply by 2: H: $2\times2=4$, S: $2\times1=2$, O: $2\times4=8$
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