QuestionJune 10, 2025

A cell phone falls off a balcony. It's height (in feet)is given by the formula f(t)=-16t^2+13.4t+150 , where t is measured in seconds. How long will it take the cell phone to hit the ground? Round your answers to three decimal places.

A cell phone falls off a balcony. It's height (in feet)is given by the formula f(t)=-16t^2+13.4t+150 , where t is measured in seconds. How long will it take the cell phone to hit the ground? Round your answers to three decimal places.
A cell phone falls off a balcony. It's height (in feet)is
given by the formula
f(t)=-16t^2+13.4t+150 , where t is measured
in seconds.
How long will it take the cell phone to hit the ground?
Round your answers to three decimal places.

Solution
4.1(242 votes)

Answer

3.515 seconds Explanation 1. Set the height equation to zero To find when the cell phone hits the ground, set f(t) = 0: -16t^2 + 13.4t + 150 = 0. 2. Use the quadratic formula **Quadratic Formula**: t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where a = -16, b = 13.4, and c = 150. 3. Calculate the discriminant Discriminant \Delta = b^2 - 4ac = (13.4)^2 - 4(-16)(150). \Delta = 179.56 + 9600 = 9779.56. 4. Solve for t using the quadratic formula t = \frac{-13.4 \pm \sqrt{9779.56}}{-32}. Calculate \sqrt{9779.56} \approx 98.89. t_1 = \frac{-13.4 + 98.89}{-32} and t_2 = \frac{-13.4 - 98.89}{-32}. t_1 \approx -2.673 (not valid as time cannot be negative). t_2 \approx 3.515.

Explanation

1. Set the height equation to zero<br /> To find when the cell phone hits the ground, set $f(t) = 0$: $-16t^2 + 13.4t + 150 = 0$.<br />2. Use the quadratic formula<br /> **Quadratic Formula**: $t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = -16$, $b = 13.4$, and $c = 150$.<br />3. Calculate the discriminant<br /> Discriminant $\Delta = b^2 - 4ac = (13.4)^2 - 4(-16)(150)$.<br /> $\Delta = 179.56 + 9600 = 9779.56$.<br />4. Solve for t using the quadratic formula<br /> $t = \frac{-13.4 \pm \sqrt{9779.56}}{-32}$.<br /> Calculate $\sqrt{9779.56} \approx 98.89$.<br /> $t_1 = \frac{-13.4 + 98.89}{-32}$ and $t_2 = \frac{-13.4 - 98.89}{-32}$.<br /> $t_1 \approx -2.673$ (not valid as time cannot be negative).<br /> $t_2 \approx 3.515$.
Click to rate: