QuestionAugust 3, 2025

Which of the following corresponds with a high change in velocity (acceleration). during a constant period of time? There is an increase in Delta p and applied force. There is a decrease in Delta p and applied force. There is an increase in Delta p and a decrease in applied force.

Which of the following corresponds with a high change in velocity (acceleration). during a constant period of time? There is an increase in Delta p and applied force. There is a decrease in Delta p and applied force. There is an increase in Delta p and a decrease in applied force.
Which of the following corresponds with
a high change in velocity (acceleration).
during a constant period of time?
There is an increase in Delta p and applied force.
There is a decrease in Delta p and applied force.
There is an increase in Delta p and a decrease in applied force.

Solution
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Answer

There is an increase in \Delta p and applied force. Explanation 1. Define the relationship between force, momentum, and acceleration **Newton's second law** states that force F is equal to the rate of change of momentum \Delta p over time t: F = \frac{\Delta p}{\Delta t}. Acceleration a is related to force by F = ma, where m is mass. 2. Analyze each option - An increase in \Delta p and applied force implies a higher rate of change of velocity (acceleration) since both \Delta p and F are directly proportional to acceleration. - A decrease in \Delta p and applied force would result in lower acceleration. - An increase in \Delta p with a decrease in applied force is contradictory under constant mass, as it would not support high acceleration.

Explanation

1. Define the relationship between force, momentum, and acceleration<br /> **Newton's second law** states that force $F$ is equal to the rate of change of momentum $\Delta p$ over time $t$: $F = \frac{\Delta p}{\Delta t}$. Acceleration $a$ is related to force by $F = ma$, where $m$ is mass.<br /><br />2. Analyze each option<br /> - An increase in $\Delta p$ and applied force implies a higher rate of change of velocity (acceleration) since both $\Delta p$ and $F$ are directly proportional to acceleration.<br /> - A decrease in $\Delta p$ and applied force would result in lower acceleration.<br /> - An increase in $\Delta p$ with a decrease in applied force is contradictory under constant mass, as it would not support high acceleration.
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