QuestionJune 25, 2025

Calculate enthalpy of the following reaction from the given bond enthalpies CH_(4(g))+2O_(2(g))arrow 2H_(2)O_((g))+CO_(2(g)) Delta H= __ . KJ Bond & }(c) Bond energy mathrm(E) / mathrm(kJ) mathrm(mol)^-1 & Bond mathrm(E) / mathrm(kJ) mathrm(mol)^-1 & Bond energy mathrm(kJ) mathrm(mol)^-1 & Bond Energy mathrm(kJ) mathrm(mol)^-1 & Bond energy mathrm(kJ) mathrm(mol)^-1 mathrm(C)-mathrm(H) & 414 & mathrm(C)-mathrm(O) & 358 & mathrm(C)=mathrm(O) & 730 mathrm(O)-mathrm(O) & 145 & mathrm(O)=mathrm(O) & 502 & mathrm(O)-mathrm(H) & 464 mathrm(H)-mathrm(H) & 435 & & & &

Calculate enthalpy of the following reaction from the given bond enthalpies CH_(4(g))+2O_(2(g))arrow 2H_(2)O_((g))+CO_(2(g)) Delta H= __ . KJ Bond & }(c) Bond energy mathrm(E) / mathrm(kJ) mathrm(mol)^-1 & Bond mathrm(E) / mathrm(kJ) mathrm(mol)^-1 & Bond energy mathrm(kJ) mathrm(mol)^-1 & Bond Energy mathrm(kJ) mathrm(mol)^-1 & Bond energy mathrm(kJ) mathrm(mol)^-1 mathrm(C)-mathrm(H) & 414 & mathrm(C)-mathrm(O) & 358 & mathrm(C)=mathrm(O) & 730 mathrm(O)-mathrm(O) & 145 & mathrm(O)=mathrm(O) & 502 & mathrm(O)-mathrm(H) & 464 mathrm(H)-mathrm(H) & 435 & & & &
Calculate enthalpy of the following reaction
from the given bond enthalpies
CH_(4(g))+2O_(2(g))arrow 2H_(2)O_((g))+CO_(2(g)) Delta H=
__ . KJ

 
Bond & }(c) 
Bond 
energy 
 mathrm(E) / mathrm(kJ) 
 mathrm(mol)^-1 
 & 
Bond 
 mathrm(E) / mathrm(kJ) 
 mathrm(mol)^-1 
 & 
Bond 
energy 
 mathrm(kJ) 
 mathrm(mol)^-1 
 & 
Bond 
Energy 
 mathrm(kJ) 
 mathrm(mol)^-1 
 & 
Bond 
energy 
 mathrm(kJ) 
 mathrm(mol)^-1 
 
 
 mathrm(C)-mathrm(H) & 414 & mathrm(C)-mathrm(O) & 358 & mathrm(C)=mathrm(O) & 730 
 
 mathrm(O)-mathrm(O) & 145 & mathrm(O)=mathrm(O) & 502 & mathrm(O)-mathrm(H) & 464 
 
 mathrm(H)-mathrm(H) & 435 & & & &

Solution
4.1(312 votes)

Answer

The final answer depends on the specific bond enthalpies provided for each bond type. Explanation 1. Identify Bonds Broken and Formed Bonds broken: 4 C-H, 2 O=O. Bonds formed: 4 O-H, 2 C=O. 2. Use Bond Enthalpies **Bond enthalpy formula:** \Delta H = \sum (\text{bonds broken}) - \sum (\text{bonds formed}). 3. Calculate Total Energy for Bonds Broken 4 \times \text{C-H} + 2 \times \text{O=O}. 4. Calculate Total Energy for Bonds Formed 4 \times \text{O-H} + 2 \times \text{C=O}. 5. Compute Enthalpy Change Substitute bond enthalpies into the formula to find \Delta H.

Explanation

1. Identify Bonds Broken and Formed<br /> Bonds broken: 4 C-H, 2 O=O. Bonds formed: 4 O-H, 2 C=O.<br /><br />2. Use Bond Enthalpies<br /> **Bond enthalpy formula:** $\Delta H = \sum (\text{bonds broken}) - \sum (\text{bonds formed})$.<br /><br />3. Calculate Total Energy for Bonds Broken<br /> $4 \times \text{C-H} + 2 \times \text{O=O}$.<br /><br />4. Calculate Total Energy for Bonds Formed<br /> $4 \times \text{O-H} + 2 \times \text{C=O}$.<br /><br />5. Compute Enthalpy Change<br /> Substitute bond enthalpies into the formula to find $\Delta H$.
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