QuestionFebruary 2, 2026

C. Full Screen Select the correct answers from the drop down menus based on this chemical reaction: NH_(3)+H_(2)Olongleftrightarrow NH_(4)^++OH^- The conjugate square of NH_(3) is square while the conjugate square of H_(2)O is square (A) Accessibility

C. Full Screen Select the correct answers from the drop down menus based on this chemical reaction: NH_(3)+H_(2)Olongleftrightarrow NH_(4)^++OH^- The conjugate square of NH_(3) is square while the conjugate square of H_(2)O is square (A) Accessibility
C. Full Screen
Select the correct answers from the drop down menus based on this chemical reaction:
NH_(3)+H_(2)Olongleftrightarrow NH_(4)^++OH^-
The conjugate square  of NH_(3) is square  while the conjugate square  of H_(2)O is square 
(A) Accessibility

Solution
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Answer

The conjugate acid of NH_{3} is NH_{4}^{+} while the conjugate base of H_{2}O is OH^{-}. Explanation 1. Identify Conjugate Acid-Base Pairs In the given chemical reaction, identify which species act as acids and bases. A conjugate acid is typically formed when a base gains a proton, while a conjugate base results when an acid loses a proton. 2. Determine Conjugate of NH_3 NH_3 acts as a base in the given reaction, accepting a proton to form NH_4^+. Therefore, the conjugate acid of NH_3 is NH_4^+. 3. Determine Conjugate of H_2O H_2O acts as an acid, donating a proton to form OH^-. Consequently, the conjugate base of H_2O is OH^-.

Explanation

1. Identify Conjugate Acid-Base Pairs<br /> In the given chemical reaction, identify which species act as acids and bases. A conjugate acid is typically formed when a base gains a proton, while a conjugate base results when an acid loses a proton.<br /><br />2. Determine Conjugate of $NH_3$<br /> $NH_3$ acts as a base in the given reaction, accepting a proton to form $NH_4^+$. Therefore, the conjugate acid of $NH_3$ is $NH_4^+$.<br /><br />3. Determine Conjugate of $H_2O$<br /> $H_2O$ acts as an acid, donating a proton to form $OH^-$. Consequently, the conjugate base of $H_2O$ is $OH^-$.<br /><br />
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