QuestionJuly 10, 2025

Multiple Choice 1 point How many moles of NO are formed if 2.50 moles of N_(2)O_(4) completely react using the balanced equation below? N_(2)H_(4)+2N_(2)O_(4)arrow 6NO+2H_(2)O 15.0 moles 10.0 moles 5.00 moles 7.50 moles

Multiple Choice 1 point How many moles of NO are formed if 2.50 moles of N_(2)O_(4) completely react using the balanced equation below? N_(2)H_(4)+2N_(2)O_(4)arrow 6NO+2H_(2)O 15.0 moles 10.0 moles 5.00 moles 7.50 moles
Multiple Choice 1 point
How many moles of NO are formed if 2.50 moles of N_(2)O_(4) completely react using the balanced equation below?
N_(2)H_(4)+2N_(2)O_(4)arrow 6NO+2H_(2)O
15.0 moles
10.0 moles
5.00 moles
7.50 moles

Solution
3.1(245 votes)

Answer

7.50 moles Explanation 1. Identify the mole ratio From the balanced equation, 2 moles of N_{2}O_{4} produce 6 moles of NO. 2. Calculate moles of NO Use the mole ratio to find moles of NO from 2.50 moles of N_{2}O_{4}: \frac{6 \text{ moles NO}}{2 \text{ moles } N_{2}O_{4}} = x \text{ moles NO}/2.50 \text{ moles } N_{2}O_{4} Solving for x: x = 2.50 \times \frac{6}{2} = 7.50 moles of NO.

Explanation

1. Identify the mole ratio<br /> From the balanced equation, 2 moles of $N_{2}O_{4}$ produce 6 moles of NO.<br /><br />2. Calculate moles of NO<br /> Use the mole ratio to find moles of NO from 2.50 moles of $N_{2}O_{4}$: <br /> $\frac{6 \text{ moles NO}}{2 \text{ moles } N_{2}O_{4}} = x \text{ moles NO}/2.50 \text{ moles } N_{2}O_{4}$<br /><br /> Solving for $x$: $x = 2.50 \times \frac{6}{2} = 7.50$ moles of NO.
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