QuestionJuly 14, 2025

Given: Al(OH)_(3)+3HNO_(3)arrow Al(NO_(3))_(3)+3H_(2)O How many moles of Al(OH)_(3) are required to react with 2.65 moles of HNO_(3)

Given: Al(OH)_(3)+3HNO_(3)arrow Al(NO_(3))_(3)+3H_(2)O How many moles of Al(OH)_(3) are required to react with 2.65 moles of HNO_(3)
Given: Al(OH)_(3)+3HNO_(3)arrow Al(NO_(3))_(3)+3H_(2)O
How many moles of Al(OH)_(3) are required to react with 2.65 moles of HNO_(3)

Solution
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Answer

0.883 moles of Al(OH)_3 are required. Explanation 1. Determine Mole Ratio From the balanced equation, 1 mole of Al(OH)_3 reacts with 3 moles of HNO_3. 2. Calculate Moles of Al(OH)_3 Use the ratio to find moles of Al(OH)_3: \frac{1 \text{ mole } Al(OH)_3}{3 \text{ moles } HNO_3} \times 2.65 \text{ moles } HNO_3 = \frac{2.65}{3}.

Explanation

1. Determine Mole Ratio<br /> From the balanced equation, 1 mole of $Al(OH)_3$ reacts with 3 moles of $HNO_3$.<br /><br />2. Calculate Moles of $Al(OH)_3$<br /> Use the ratio to find moles of $Al(OH)_3$: $\frac{1 \text{ mole } Al(OH)_3}{3 \text{ moles } HNO_3} \times 2.65 \text{ moles } HNO_3 = \frac{2.65}{3}$.
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