QuestionJuly 22, 2025

Multiply across the bottom of the unit conversion. What is the product of the denominator? (24molesC_(2)H_(6)vert 7molesO_(2))/(2molesC_(2)H_(6))=(168)/([?]) Do not round or reduce the answer.

Multiply across the bottom of the unit conversion. What is the product of the denominator? (24molesC_(2)H_(6)vert 7molesO_(2))/(2molesC_(2)H_(6))=(168)/([?]) Do not round or reduce the answer.
Multiply across the bottom of the unit
conversion. What is the product of the
denominator?
(24molesC_(2)H_(6)vert 7molesO_(2))/(2molesC_(2)H_(6))=(168)/([?])
Do not round or reduce the answer.

Solution
4.7(260 votes)

Answer

14 Explanation 1. Identify the denominator values The denominator consists of 7 \text{ moles } \mathrm{O}_{2} and 2 \text{ moles } \mathrm{C}_{2} \mathrm{H}_{6}. 2. Multiply the denominator values Multiply 7 by 2: 7 \times 2 = 14.

Explanation

1. Identify the denominator values<br /> The denominator consists of $7 \text{ moles } \mathrm{O}_{2}$ and $2 \text{ moles } \mathrm{C}_{2} \mathrm{H}_{6}$.<br /><br />2. Multiply the denominator values<br /> Multiply $7$ by $2$: $7 \times 2 = 14$.
Click to rate:

Similar Questions