QuestionJune 18, 2025

How many oxygen atoms are found in a 33 g sample of manganese(III)nitrite? A. 2.06times 10^23 0 atoms 8 7 25 N Mn 16.00 14.01 54.94 B. 4.57times 10^23 0 atoms C. 5.10times 10^23 0 atoms D. 6.18times 10^23 O atoms E. . 7.42times 10^23 0 atoms

How many oxygen atoms are found in a 33 g sample of manganese(III)nitrite? A. 2.06times 10^23 0 atoms 8 7 25 N Mn 16.00 14.01 54.94 B. 4.57times 10^23 0 atoms C. 5.10times 10^23 0 atoms D. 6.18times 10^23 O atoms E. . 7.42times 10^23 0 atoms
How many oxygen atoms are found in a 33 g sample of
manganese(III)nitrite?
A. 2.06times 10^23 0 atoms
8	7 25
N Mn
16.00 14.01 54.94
B. 4.57times 10^23 0 atoms
C. 5.10times 10^23 0 atoms
D. 6.18times 10^23 O atoms
E. . 7.42times 10^23 0 atoms

Solution
4.6(204 votes)

Answer

6.68\times 10^{23} oxygen atoms Explanation 1. Determine the Molar Mass of Manganese(III) Nitrite The formula is Mn(NO_2)_3. Calculate molar mass: Mn = 54.94, N = 14.01, O = 16.00. Total: 54.94 + 3 \times (14.01 + 2 \times 16.00) = 178.95 g/mol. 2. Calculate Moles of Manganese(III) Nitrite Use **moles = \frac{\text{mass}}{\text{molar mass}}**: \frac{33}{178.95} \approx 0.1844 moles. 3. Calculate Number of Oxygen Atoms Each molecule has 6 oxygen atoms. Total oxygen atoms = 0.1844 \times 6 \times 6.022 \times 10^{23}.

Explanation

1. Determine the Molar Mass of Manganese(III) Nitrite<br /> The formula is $Mn(NO_2)_3$. Calculate molar mass: $Mn = 54.94$, $N = 14.01$, $O = 16.00$. Total: $54.94 + 3 \times (14.01 + 2 \times 16.00) = 178.95$ g/mol.<br />2. Calculate Moles of Manganese(III) Nitrite<br /> Use **moles = \frac{\text{mass}}{\text{molar mass}}**: $\frac{33}{178.95} \approx 0.1844$ moles.<br />3. Calculate Number of Oxygen Atoms<br /> Each molecule has 6 oxygen atoms. Total oxygen atoms = $0.1844 \times 6 \times 6.022 \times 10^{23}$.
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