QuestionJune 18, 2025

Consider the following compounds. Which is insoluble? VI_(2) HgBr_(2) ONaBr NaCl All of these None of these

Consider the following compounds. Which is insoluble? VI_(2) HgBr_(2) ONaBr NaCl All of these None of these
Consider the following compounds. Which is insoluble?
VI_(2)
HgBr_(2)
ONaBr
NaCl
All of these
None of these

Solution
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Answer

\mathrm{HgBr}_{2} Explanation 1. Identify Solubility Rules Sodium salts (e.g., NaBr, NaCl) are generally soluble in water. Most halides are soluble except for those of silver, lead, and mercury. 2. Analyze Each Compound VI_2: No common solubility rule applies; assume insoluble unless specified otherwise. HgBr_2: Mercury(II) bromide is an exception to the general solubility of bromides, making it insoluble. NaBr and NaCl: Both are sodium salts and are soluble. 3. Determine Insoluble Compound Based on the analysis, HgBr_2 is insoluble.

Explanation

1. Identify Solubility Rules<br /> Sodium salts (e.g., NaBr, NaCl) are generally soluble in water. Most halides are soluble except for those of silver, lead, and mercury.<br />2. Analyze Each Compound<br /> $VI_2$: No common solubility rule applies; assume insoluble unless specified otherwise.<br /> $HgBr_2$: Mercury(II) bromide is an exception to the general solubility of bromides, making it insoluble.<br /> $NaBr$ and $NaCl$: Both are sodium salts and are soluble.<br />3. Determine Insoluble Compound<br /> Based on the analysis, $HgBr_2$ is insoluble.
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