QuestionJune 18, 2025

A gas occupies 667.9 mL at a temperature of 26.4^circ C What is the volume of gas at 122.87^circ C assuming pressure did not change? Give your answer in L to the hundredths place. Do not put units in the answer space.

A gas occupies 667.9 mL at a temperature of 26.4^circ C What is the volume of gas at 122.87^circ C assuming pressure did not change? Give your answer in L to the hundredths place. Do not put units in the answer space.
A gas occupies 667.9 mL at a temperature of 26.4^circ C What is the volume of gas at 122.87^circ C
assuming pressure did not change?
Give your answer in L to the hundredths place. Do not put units in the answer space.

Solution
4.3(209 votes)

Answer

0.88 Explanation 1. Convert Temperatures to Kelvin T_1 = 26.4^{\circ}C + 273.15 = 299.55 \, K; T_2 = 122.87^{\circ}C + 273.15 = 396.02 \, K 2. Apply Charles's Law **Charles's Law**: \frac{V_1}{T_1} = \frac{V_2}{T_2} 3. Solve for V_2 V_2 = V_1 \times \frac{T_2}{T_1} = 667.9 \, mL \times \frac{396.02 \, K}{299.55 \, K} 4. Convert Volume to Liters V_2 = 884.0 \, mL = 0.884 \, L

Explanation

1. Convert Temperatures to Kelvin<br /> $T_1 = 26.4^{\circ}C + 273.15 = 299.55 \, K$; $T_2 = 122.87^{\circ}C + 273.15 = 396.02 \, K$<br /><br />2. Apply Charles's Law<br /> **Charles's Law**: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$<br /><br />3. Solve for $V_2$<br /> $V_2 = V_1 \times \frac{T_2}{T_1} = 667.9 \, mL \times \frac{396.02 \, K}{299.55 \, K}$<br /><br />4. Convert Volume to Liters<br /> $V_2 = 884.0 \, mL = 0.884 \, L$
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