Determine the LCM or GCF for each. GCF(8,27,35)
Look at this equation: v^3=1 What is v, the cube root of 1? V= square
Simplify the expression to a+bi form: (7+i)-(-9+i) Answer Attempt 1 out of 3 square
Subtract. Write your answer in simplest form. -4sqrt (147)-9sqrt (3) square
Solve for p. (p)/(-8)=-7 p= square
-(5)/(6)-(3)/(4)-(-(7)/(3))=
16. List all sets of numbers (number systems) to which sqrt (15) belongs.
2. Write 1.888 __ as a mixed number. Letx=square . 10x=square 10x-x=square -square 9x=square x=square So 1.888 __ is equal to square
4. Find f(x+3) if f(x)=5x-2 Calcula f(x+3) si
(c^2-1)/(c^4)-1div (c+1)/(c^2)+1
Apply the distributive property to the expression. $100(0.07a+0.02b)=\square $
51. Find the volume of a pyramid with a square base, where the perimeter of the base is 15.8 ft and the height of the pyramid is 20.4 ft. Round your answer to the nearest tenth of a cubic foot.
4) $v^{1}=$ A) 0 B) 1 OC) v OD) $1/v$
What is the range of the function graphed above? $-\infty \lt y\leqslant 2$ $-\frac {3}{2}\leqslant y\lt \infty $ $-\infty \lt y\lt \infty $ $\{ 2\} $
2. You are inscribing a regular pentagon in a cIrcle. You need to know the angle measure between the vertices. You divide $360^{\circ }$ by what number? 3 s 6
Which equation represents a line that has a slope of $-\frac {1}{2}$ and passes through point $(4,-5)$ $y=-\frac {1}{2}x+\frac {3}{2}$ $y=-\frac {1}{2}x+\frac {13}{2}$ $y=-\frac {1}{2}x-7$ $y=-\frac {1}{2}x-3$
Smartphones: A poll agency reports that $38\% $ of teenagers aged $12-17$ own smartphones. A random sample of 120 teenagers is drawn. Round your answers to at least four decimal places as needed Part: 0/6 Part 1 of 6 (a) Find the mean $\mu _{\hat {p}}$ The mean $\mu _{\hat {p}}$ is 45.6000 Part: 1/6 Part 2 of 6 (b) Find the standard deviation $\sigma _{\hat {p}}$ The standard deviation $\sigma _{\hat {p}}$ is $\square $
1. If $x+3=7$ then x equals: A. 3 B. 4 C. 5 D. 10
Find the angle $\beta $ between $0^{\circ }$ and $180^{\circ }$ that satisfies the following equation. $21^{2}=20^{2}+29^{2}-(2)(20)(29)cos\beta $ $\beta \approx \square ^{\circ }$ (Round to one decimal place as needed.)
Solve the equation given by completing the square. $5x^{2}+20x-25=0$ [Hint: Divide by 5 first] $x=\square $