Simplify the expression. k^9cdot k^-3
Subtract. (1)/(6)-(-(7)/(8)) (25)/(24) -(1)/(6) -(17)/(24) -(25)/(24)
Is the open sentence 3z=2z+5 true or false when z=5 true false
Find the 72nd term of the arithmetic sequence -27,-11,5,ldots Answer Attempt 1 out of 2 square
5. 3^-2cdot 3^3x-7=((1)/(27))^2x+15
Find the distance between E and F on the number line below. Distance: square
Solve the equation 2(p-6)=4(2p-3) p= square
Add. (2)/(3)+(-(4)/(9)) -(10)/(9) (2)/(9) (10)/(9) -(2)/(9)
3. 7(1)/(6)-4(2)/(3)=underline ( )
3. Let g be a function defined by g(x) where g(x)= ) (-1)/(2)x^2+3,&ifxlt 1 2x^2+1,&ifxgeqslant 1 Find g(-1),g(0),g(1),g(2)
Apply the distributive property to the expression. $100(0.07a+0.02b)=\square $
51. Find the volume of a pyramid with a square base, where the perimeter of the base is 15.8 ft and the height of the pyramid is 20.4 ft. Round your answer to the nearest tenth of a cubic foot.
4) $v^{1}=$ A) 0 B) 1 OC) v OD) $1/v$
What is the range of the function graphed above? $-\infty \lt y\leqslant 2$ $-\frac {3}{2}\leqslant y\lt \infty $ $-\infty \lt y\lt \infty $ $\{ 2\} $
2. You are inscribing a regular pentagon in a cIrcle. You need to know the angle measure between the vertices. You divide $360^{\circ }$ by what number? 3 s 6
Which equation represents a line that has a slope of $-\frac {1}{2}$ and passes through point $(4,-5)$ $y=-\frac {1}{2}x+\frac {3}{2}$ $y=-\frac {1}{2}x+\frac {13}{2}$ $y=-\frac {1}{2}x-7$ $y=-\frac {1}{2}x-3$
Smartphones: A poll agency reports that $38\% $ of teenagers aged $12-17$ own smartphones. A random sample of 120 teenagers is drawn. Round your answers to at least four decimal places as needed Part: 0/6 Part 1 of 6 (a) Find the mean $\mu _{\hat {p}}$ The mean $\mu _{\hat {p}}$ is 45.6000 Part: 1/6 Part 2 of 6 (b) Find the standard deviation $\sigma _{\hat {p}}$ The standard deviation $\sigma _{\hat {p}}$ is $\square $
1. If $x+3=7$ then x equals: A. 3 B. 4 C. 5 D. 10
Find the angle $\beta $ between $0^{\circ }$ and $180^{\circ }$ that satisfies the following equation. $21^{2}=20^{2}+29^{2}-(2)(20)(29)cos\beta $ $\beta \approx \square ^{\circ }$ (Round to one decimal place as needed.)
Solve the equation given by completing the square. $5x^{2}+20x-25=0$ [Hint: Divide by 5 first] $x=\square $