Factor the polynomial f(x) Then solve the equation f(x)=0 f(x)=x^3-9x^2+11x+21 The factored form is f(x)=(x+1)(x-3)(x-7) The solution(s) to f(x)=0 is(are) x=-1,3,7 (Use commas to separate answers as needed. If a solution occurs more than once, type the solution only once.)
Solve the inequality algebraically. (5)/(x-5)gt (8)/(3x-3) The solution is square (Simplify your answer. Type your answer i in interval notation. Use integers or fractions for any numbers in the expression.)
The factors of x^2-8xy+15y^2 are A (x-15y)(x-y) B (x+15y)(x+y) (x+5y)(x+3y) D (x-5y)(x-3y)
What is the shape of the data if mean=median Symmetric Skewed left Skewed right Scalene triangle
Instructions: The discriminant is a part of which method? Select one: Completing the Square Factoring Quadratic Formula Square Roots
The partial fraction decomposition of (6)/((x-1)(x+1)) can be written in the form of (f(x))/(x-1)+(g(x))/(x+1) where f(x)=square g(x)=square
Which expression is equivalent to sqrt [4]((24x^6y)/(128x^4)y^5) Assume xneq 0 and ygt 0 (sqrt [4](3))/(2x^2)y (x(sqrt [4](3)))/(4y^2) (sqrt [4](3))/(4xy^2) (sqrt [4](3x^2))/(2y)
Express as a trinomial. (3x+4)(2x+4) Answer Attempt 1 out of 2 square
One factor of f(x)=x^3-14x^2+61x-84 is (x-7) What are the zeros of the function? 7,4,-3 7,4,3 7,-4,-3 7,-4,3
Multiply (x-4)(x^2-3x+5) x^3+5x^2+5x-20 x^3+2x^2+8x-20 x^3-x^2+7x-20 x^3-7x^2+17x-20
Find the perimeter of the triangle with these vertices. $(4,3),(-3,3),(-3,-3)$ Give an exact answer (not a decimal approximation). Simplify your answer as much as possible.
) Select all the factor pairs of 28. 4 and 6 2 and 14 3 and 7 1 and 28 4 and 7 3 and 9
8) $\frac {2\sqrt [5]{5p^{2}}}{\sqrt [5]{16p}}$
Solve. $6x^{\wedge }4-7x^{\wedge }2+2=0$
8. Which of these below correctly solves for yof the equation $3x-2=4y+5$ $y=-3x-5$ $y=-\frac {3}{4}x+\frac {7}{4}$ $y=\frac {3}{4}x-\frac {7}{4}$ $y=3x+5$
2. What value of x makes this equation true? $6-x=5x+30$
4)) Find the number that makes the ratio equivalent to $2:11$ $\square :88$
5) Solve the equation below for III. $-8=\frac {m+7}{-4}$
Solve the equation a $0=x^{3}-4x^{2}-21x$ b $2x^{4}-6x^{3}=12x^{2}-36x$
\( 3 x + 2 \longdiv { 9 x ^ { 3 } + 2 7 x ^ { 2 } + 1 7 x + 2 } \)
